This exercise combines concepts from the previous two problems: using a constant for preparation time (multiplication) and summing two time values (addition) to find a total elapsed time. This demonstrates how to combine multiple arithmetic operations in a single formula.
Problem Statement:
You need to calculate the total elapsed cooking time, which is the sum of the preparation time and the time the lasagna has already spent baking.
- Preparation Rate: Each layer (N) takes 2 minutes to prepare.
- Baking Time: The lasagna has already been baking for M minutes.
Find the total time: (N × 2) + M
| Input N (Layers) | Input M (Bake Time) | Calculation | Output (Total Time) |
| 3 | 20 | (3 × 2) + 20 = 6 + 20 | 26 |
| 1 | 29 | (1 × 2) + 29 = 2 + 29 | 31 |
💡 Java Solution Breakdown
The solution involves reading two separate integer inputs, performing multiplication with a constant, and then using the addition operator to sum the result with the second input.
1. Complete Java Code
import java.util.Scanner;
public class TotalElapsedCookingTime {
/** * Define the constant time required for one layer of preparation.
*/
public static final int MINUTES_PER_LAYER = 2;
public static void main(String[] args) {
// 1. Initialize the Scanner object for input.
Scanner sc = new Scanner(System.in);
// 2. Read the first input: Number of layers (N).
int numberOfLayers = sc.nextInt();
// 3. Read the second input: Minutes already baked (M).
int minutesAlreadyBaked = sc.nextInt();
sc.close();
// 4. Calculate preparation time: N * 2
int prepTime = numberOfLayers * MINUTES_PER_LAYER;
// 5. Calculate total elapsed time: Prep Time + Bake Time
int totalTime = prepTime + minutesAlreadyBaked;
//
// 6. Print the final result.
System.out.println(totalTime);
}
}
2. Key Concepts & Learning Points
| Concept | Description |
| Handling Multiple Inputs | The program uses sc.nextInt() twice in sequence to correctly read the two separate input lines, N and M. |
| Combined Operations | The key calculation (prepTime + minutesAlreadyBaked) demonstrates the order of operations: multiplication (*) is performed first to get prepTime, and then addition (+) sums the results. |
| Code Readability | Using an intermediate variable (prepTime) makes the final calculation (totalTime = prepTime + minutesAlreadyBaked;) much cleaner and easier to understand. |
